UC知道c++编程啊
来源：百度知道 编辑：UC知道 时间：2024/06/21 22:49:08
#include<stdio.h>
main()
{
int i,m=1;
char t;
printf("please input a number:\n");
scanf("%d",&i);
for(m=1;m<11;m++)
{
printf("%d*%d=%d",i,m,i*m);
printf(" ");
if(m%2= =0)
printf("\n");
}
此程序再加几句使他运行一次后
运行窗口出现"是否继续运行Y/N"该怎么办?
main()
{
int i,m=1;
char t;
printf("please input a number:\n");
scanf("%d",&i);
for(m=1;m<11;m++)
{
printf("%d*%d=%d",i,m,i*m);
printf(" ");
if(m%2= =0)
printf("\n");
}
此程序再加几句使他运行一次后
运行窗口出现"是否继续运行Y/N"该怎么办?
main()
{
char c ;
do
{
你的代码
printf("是否继续Y/N");
scanf(%c,&c)
}while(c=="N"||c=="n");
}
使用前将 4 个 "`" 替换为一个 TAB 符
#include <stdio.h>
#include <stdlib.h>
void main(void)
{
````int i,m=1;
````char t;
````printf("please input a number:\n");
````scanf("%d",&i);
````for(m=1;m<11;m++)
````{
````````printf("%d*%d=%d",i,m,i*m);
````````printf(" ");
````````if(m%2= =0) printf("\n");
````````
````````printf("Continue or not?(Y/N) "); t = getch();
````````while (t != 'y' && t != 'Y' && t != 'n' && t != 'N') t = getch();
````````
````````printf("%c", t);
````````if (t == 'n' || t == 'N') break;
````````printf("\n");
````}
}
建议用C+