who can translate this for me?help me,please T T

来源：百度知道 编辑：UC知道 时间：2024/05/28 06:54:33
Rather than using a k-universal hash function, we chose to use the standard SHA-1 function as our base hash function. This makes our protocol deterministic, so that the claims of “high probability”no longer make sense. However,producing a set of keys that collide under SHA-1 can be seen, in some sense, as inverting, or“decrypting” the SHA-1 function. This is believed to be hard to do. Thus,instead of stating that our theorems hold with high probability, we can claim that they hold “based on standard hardness assumptions.”

不愿使用 a k-通用的一混杂函数, 我们选择以标准的 SHA-1 函数作为 , 我们的碱切碎函数。 这使我们的协定决定论,所以 " 高的或然率 " 的赔偿不再有道理。 然而，产生依据 SHA-1 规定碰撞的一组锁匙能被预期,在一些感官,当做反对的, 或 " 解密 " SHA-1 函数。 这被相信到 , 对同前要硬式因此,而非陈述我们的定理赞同高的或然率, 我们能声称他们持平 "以标准的硬度假设为基础。”