(7/X-4)-(5/X-2)=0
来源:百度知道 编辑:UC知道 时间:2024/05/05 09:40:20
(7/X-4)-(5/X-2)=0
[7(X-2)-5(X-4)]/[(X-2)(X-4)]=0
7(X-2)-5(X-4)=0
7X-14-5X+20=0
2X=-6
X=-3,
代入检验,成立
7/x-4=5/x-2
7-4x=5-2x
2=2x
x=1
解:7/(x-4)=5/(x-2)
7(x-2)=5(x-4)
7x-14=5x-20
2x=-6
x=-3
7/(x-4)=5/(x-2)
7(x-2)=5(x-2)
7x-14=5x-10
2x=4
x=2
因为方程x不等于2
所以为增根
方程无解
哈哈 7/(x-4)=5/(x-2)
7(x-2)=5(x-2)
7x-14=5x-10
2x=4
x=2
x-5/x-7+x-2/x--4=x-3/x-5+x-4/x-6
解因式方程:x-4/x-5+x-8/x-9=x-7/x-8+x-5/x-6
方程(x+2)/(x+1)-(x+4)/(x+3)=(x+6)/(x+5)-(x+8)/(x+7)
(x+1)/[7x^9+Kx^8+3x^5+5x^4+7]
[x+2]/[x+1]-[x+4]/[x+3]-[x+3]/[x+2]+]x+5]/[x+4]
2/1X+12/1X+7/1X+6/1X+5+4=X
x+x^2+x^3+x^4+x^5+...+x^12=500/12
若整数x同时满足5x+5/7>4x+5和7x+3<5x+26则x满足_____
1/x-1 +1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+1/(x-4)(x-5)
5x/(x^2+x-6)+(2x-5)/(x^2-x-12)=(7x-10)/(x^2-6x+8)