帮忙解初三的一元2次方程！在线等 急！

3(2-y)^2=y(y-2)
(y-2)(3y-6-y)=0
y=2或y=3
2(x+1)^2=x^2-1
(x+1)(2x+2-x+1)=0
x=-1或x=-3
x^2+4x-1=0
(x+2)^2=5
则x+2=根号5或-根号5
x=根号5-2或-根号5-2
x^2+3x+2=0
(x+1)(x+2)=0
x=-1或x=-2
x^2+4x+4=0
(x+2)^2=0
则x=-2

3（2-y)^2=y(y-2)
3(4-4y+y^2)=y^2-2y
2y^2-10Y+12
(y-2)(2y-6)
y1=2,y2=3

2(x+1)^2=x^2-1
2x^2+4x+2-x^2+1=0
x^2+4x+3=0
(x+1)(x+3)=0
x1=-1,x2=-3

x^2+4x-1=0
(x+2)^2=5
则x+2=根号5或-根号5
x=根号5-2或-根号5-2

x^2+3x+2=0
(x+1)(x+2)=0
x1=-1,x2=-2

x^2+4x+4=0
(x+2)^2=0
x1=x2=-2