问个数学小问题(就一个填空)

来源:百度知道 编辑:UC知道 时间:2024/05/29 06:24:41
计算(2+1)(2^2+1)(2^4+1)... ..._(2^(2n)+1)=________

(2+1)(2^2+1)(2^4+1)... ..._(2^(2n)+1)
=(2-1)(2+1)(2^2+1)(2^4+1)... ..._(2^(2n)+1)
=(2^2-1)(2^2+1)(2^4+1)... ..._(2^(2n)+1)
=..
=(2^2n-1)(2^2n+1)
=2^(4n)-1

原式=(2-1)*(2+1)(2^2+1)(2^4+1)... ..._(2^(2n)+1)
(2^2-1)(2^2-+)(2^4+1)... ..._(2^(2n)+1)
=(2^4-1)(2^4+1)……...(2^(2n)+1)
……
=(2^(2n)-1)(2^(2n)+1)=2^(4n)-1

乘以(2-1),因为2-1=1
所以结果不变
(2-1)(2+1)(2^2+1)(2^4+1)... ..._(2^(2^n)+1)
=(2^2-1)(2^2+1)(2^4+1)... ..._(2^(2^n)+1)
=(2^4-1)(2^4+1)... ..._(2^(2^n)+1)
=……
=2^[2^(n+1)]-1