UC知道asp+access，怎么样才可以把下拉菜单中提交的内容写入数据库,,
来源：百度知道 编辑：UC知道 时间：2024/06/22 03:39:03
我要做的是一个WAP网友自拍小系统,,分类在数据库里命名为class,,上传后的图片都放在了data里,,,但上传后的图片都没有显示有分类,,,这个要怎么做,,我那个源码是这样的,,
<%
if Session("zh")="wap" then
response.redirect "/lt/yksm.asp"
else
Session("ltlybz")=""
End if
wap=request.querystring("wap")
iduse=Session("useid")
sq1="select * from upset where id=1"
Set Rs1 = Server.CreateObject("Adodb.Recordset")
rs1.open sq1,conn,1,2
rslassid=request("lassid")
rstitle=c2u(rs1("title"))
rsformPath=rs1("formPath")
rsnamekind=rs1("namekind")
rsfilesize=rs1("filesize")
rsallowedfile=rs1("allowedfile")
rsforceup=rs1("forceup")
rs1.close
Set rs1=nothing
%>
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//WAPFORUM//DTD XHTML Mo
<%
if Session("zh")="wap" then
response.redirect "/lt/yksm.asp"
else
Session("ltlybz")=""
End if
wap=request.querystring("wap")
iduse=Session("useid")
sq1="select * from upset where id=1"
Set Rs1 = Server.CreateObject("Adodb.Recordset")
rs1.open sq1,conn,1,2
rslassid=request("lassid")
rstitle=c2u(rs1("title"))
rsformPath=rs1("formPath")
rsnamekind=rs1("namekind")
rsfilesize=rs1("filesize")
rsallowedfile=rs1("allowedfile")
rsforceup=rs1("forceup")
rs1.close
Set rs1=nothing
%>
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//WAPFORUM//DTD XHTML Mo
sq1="select * from upset where id=1"
Set Rs1 = Server.CreateObject("Adodb.Recordset")
rs1.open sq1,conn,1,2
rslassid=request("lassid")
rstitle=c2u(rs1("title"))
rsformPath=rs1("formPath")
rsnamekind=rs1("namekind")
rsfilesize=rs1("filesize")
rsallowedfile=rs1("allowedfile")
rsforceup=rs1("forceup")
这里少rs.updata
rs1.close
Set rs1=nothing
rslassid=request("lassid") '楼主这裏写错了吧,写错地方为rslassid
是否为rs1("lassid")=request("lassid")