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(log4^3+log8^3)(log3^2+log9^2)-log2^(根号32开4次方)
=[log4^3+log(4^2)^3][log3^2+log(3^2)^2]-log2^2√2
=[log4^3+log4^6][log3^2+log3^4]-log2^2√2
=log4^9*log3^8-log2^2-log2^√2
=lg9/lg4*lg8/lg3-1-1/2
=3-2√2

前提 log2^3 当成以2为底 3的对数理解的

(log4^3+log8^3)(log3^2+log9^2)-log2^
=(6log2+9log2)(2log3+4log3))-log2^
=(15log2)*(6log3)-2log2
=90log2*log3-2log2
剩下就不会了~~

我才小学六年级～～～～～5555～～～没学啊