2元1次方程组
来源:百度知道 编辑:UC知道 时间:2024/05/18 10:46:06
4(x-y-1)=3(1-y)-2
x\2+y/3=2
2(x-y)/3-x+y\4=-1
6(x+y)-4(2x-y)=16
x\2+y/3=2
2(x-y)/3-x+y\4=-1
6(x+y)-4(2x-y)=16
4(x-y-1)=3(1-y)-2 [1]
x\2+y/3=2 [2]
由[1]得,4x-y=5,y=4x-5[3], 由[2]得,3x+2y=12[4]
把[3]带入[4] ,得 x=2, 因此,y=3.
2(x-y)/3-x+y\4=-1[1]
6(x+y)-4(2x-y)=16[2]
由[1]得,4x+5y=12 [3],
由[2]得,5y-x=8, [4],
[3]-[4]得,5x=4,即 x=4/5,所以,y=44/25
x=2
y=3
x=44/25
y=4/5
(1) x=2 y=3
(2) x=4/5 y=44/25