几个初2分解因式的题目

注意"^"代表乘方 例如:m^2的意思是m的平方
1.m^2-4n^2-4n-1
2.a^2-b^2-1+2b
3.已经知道x^2=x-1 则x^2000-x^1999+x^1998=多少?
4.-3x^n+1+6x^n-3x^n-1

我需要具体过程 不能直接告诉我结果 谢谢

1.m^2-4n^2-4n-1
=m^2-(4n^2+4n+1)
=m^2-(2n+1)^2
=(m+2n+1)*(m-2n-1)

2.a^2-b^2-1+2b
=a^2-(b^2+1-2b)
=a^2-(b-1)^2
=(a-b+1)*(a+b-1)

3.x^2=x-1
x^2-x+1=0

x^2000-x^1999+x^1998
=x^1998(x^2-x+1)
=0

4.-3x^n+1+6x^n-3x^n-1
=-3x^(n-1)(x^2-2x+1)
=-3x^(n-1)(x-1)^2

1.=m^2-(2n+1)^2
=(m+2n+1)(m-2n-1)
2.=a^2-(b-1)^2
=(a+b-1)(a-b+1)
3.x^1998*(x^2-x+1)=1998*0=0
4.=6x^n-6x^n+2=2

解:
1.m^2-(4n^2+4n+1)
=m^2-(2n+1)^2
=(m+2n+1)(m-2n-1)

2.a^2-(b^2+1-2b)
= a^2-(b-1)^2
=(a+b-1)(a-b+1)

3.
因为x^2=x-1
所以x^2-x+1=0
x^2000-x^1999+x^1998
=x^1998(x^2-X+1)
=0
4.3x^n+1:3倍x的n+1次方?
-3x^n+1+6x^n-3x^n-1
=-3x^(n-1) (x^2-2x+1)
=-3x^(n-1) (x-1)^2

3x^n+1:3倍x的n次方+1?
-3x^n+1+6x^n-3x^n-1=6x^n-6x^n-1+1=0

楼上的“她是朋友吗 ”，你好厉害，可以认识一下吗 Q;380313101

1.=m^2-(4n^2+4n+1)
=m^2-(2n+1)^2