UC知道VB 问题，请大家帮忙啊！
来源：百度知道 编辑：UC知道 时间：2024/05/25 19:47:28
在vb中我想用二维数组，所以定义如下
option base 1
dim graph(5) as variant
dim distance(5) as integer
graph(1)(5)="1,0,1,0,1"
graph(2)(5)="0,1,0,1,0"
graph(3)(5)="1,0,1,0,1"
graph(4)(5)="0,0,1,1,0"
graph(5)(5)="1,1,0,0,1"
for i=1 to 5
distance(i)=graph(1)(i)
为什么老说graph类型不匹配阿？！
请哪位高手帮忙解决一下阿？！谢谢！！
option base 1
dim graph(5) as variant
dim distance(5) as integer
graph(1)(5)="1,0,1,0,1"
graph(2)(5)="0,1,0,1,0"
graph(3)(5)="1,0,1,0,1"
graph(4)(5)="0,0,1,1,0"
graph(5)(5)="1,1,0,0,1"
for i=1 to 5
distance(i)=graph(1)(i)
为什么老说graph类型不匹配阿？！
请哪位高手帮忙解决一下阿？！谢谢！！
Dim graph(1 To 5) As Variant
Dim distance(1 To 5) As Variant
graph(1) = Array(1, 0, 1, 0, 1)
graph(2) = Array(0, 1, 0, 1, 0)
graph(3) = Array(1, 0, 1, 0, 1)
graph(4) = Array(0, 0, 1, 1, 0)
graph(5) = Array(1, 1, 0, 0, 1)
For i = 1 To 5
distance(i) = graph(i)
Next
End Sub
graph(1)=array(1,0,1,0,1)
graph(2)=array(0,1,0,1,0)
graph(3)=array(1,0,1,0,1)
graph(4)=array(0,0,1,1,0)
graph(5)=array(1,1,0,0,1)
和1楼一样= =见识了。。。二维数组可以这样定义呀，。。
........
恕我古董。。。。二维数组现在已经可以这样定义的吗。。。。没有听说啊
不是dim a (10，10) as integer 的吗？