2(x-6)+1/3x=9这道方程怎么解?
来源:百度知道 编辑:UC知道 时间:2024/05/03 02:18:43
如题
2(x-6)+1/3x=9
解:2x-2×6+1/3x=9
2又1/3x-12=9
2又1/3x=21
x=9
方程左右都乘以3x得6x(x-6)+1=27x
移项得6x×x-36x-27x=0
合并同类项得:6x×x-63x=0
提出x:x(6x-63)=0
x=0或者x=63/6
2(x-6)+1/3x=9
2x-12+1/3x=9
7/3x=21
x=9
x-1/x^2+3x+2+6/2+x-x^2-10-x/4-x^2
(x+1/x+2)-(1/x+7)=(x+2/x+3)-(1/x+6)
计算:(x+1)(x-2)(x-3)(x-6)
分式方程问题:解方程:[x+1)/(x+2)]+[(x+6)/(x+7)]=[(x+2)/(x+3)]+[(x+5)/(x+6)]
x^2-3x+1=0,求2x^5-5x^4-x^3+x^2-6x/x^2+1
(x+2/x+1)+ (x+6/x+5)=(x+3/x+2)+(x+5/x+4)怎么解?
x+1/x=3,求(x^10+x^8+x^2+1)/(x^10+x^6+x^4+1)的值
方程(x+2)/(x+1)-(x+4)/(x+3)=(x+6)/(x+5)-(x+8)/(x+7)
[x+2]/[x+1]-[x+4]/[x+3]-[x+3]/[x+2]+]x+5]/[x+4]
x^6+x^5+x^4+x^3+x^2+x+1=0