java中通过按钮退出用户界面

来源：百度知道 编辑：UC知道 时间：2024/06/17 17:48:16
今天写了一段代码,但是无法通过建立的按钮退出界面,问题在代码中,代码如下:
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.sql.*;

class login extends JFrame implements ActionListener,ItemListener
{
Button buttonone,buttontwo;
login(String s)
{
super(s);
//欢迎界面
JLabel labelone=new JLabel(new ImageIcon("login.jpg")),
labeltwo=new JLabel("UID"),
labelthree=new JLabel("Password");
JPanel panelone=new JPanel(),
paneltwo=new JPanel();
//panelone中为登陆信息
panelone.add(labeltwo);
JTextField textone=new JTextField(16);
//textone.addActionListener(this);
panelone.add(textone);
panelone.add(labelthree);
JPasswordField passone=new JPasswordField(16);
//passone.addActionListener(this);
panelone.add(passone);
//paneltwo中为权限选择
JRadioButton radioone=new JRadioButton("学生"),
radiotwo=new JR

import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.sql.*;

class login extends JFrame implements ActionListener,ItemListener
{
JButton buttonone,buttontwo;
login(String s)
{
super(s);
//欢迎界面
JLabel labelone=new JLabel(new ImageIcon("login.jpg")),
labeltwo=new JLabel("UID"),
labelthree=new JLabel("Password");
JPanel panelone=new JPanel(),
paneltwo=new JPanel();
//panelone中为登陆信息
panelone.add(labeltwo);
JTextField textone=new JTextField(16);
//textone.addActionListener(this);
panelone.add(textone);
panelone.add(labelthree);
JPasswordField passone=new JPasswordField(16);
//passone.addActionListener(this);
panelone.add(passone);
//paneltwo中为权限选择
JRadioButton radioone=new JRadioButton("学生"),
radiotwo=new JRadioButton("教师"),
radiothree=new JRad