matlab中用逆矩阵法,solve,rref法求解线性方程组的解.2x+3y+z=5 2x+3y+z=8

A=[ 2 3 1
3 2 5
1 3 2];
b1=[5 7 6]';
b2=[8 9 10]';

逆矩阵
rats(inv(A)*b1)

ans =

-1/9
13/9
8/9

rats(inv(A)*b2)

ans =

-5/6
17/6
7/6

solve:
res=solve('2*x+3*y+z=5','3*x+2*y+5*z=7','x+3*y+2*z=6');[res.x res.y res.z]

ans =

[ -1/9, 13/9, 8/9]

res=solve('2*x+3*y+z=8','3*x+2*y+5*z=9','x+3*y+2*z=10');[res.x res.y res.z]

ans =

[ -5/6, 17/6, 7/6]

rref法：
R=rref([A b1])

R =
1 0 0 -1/9
0 1 0 13/9
0 0 1 8/9

R=rref([A b2])

R =

1 0 0 -5/6
0 1 0 17/6