UC知道java中map统计，排序问题
来源：百度知道 编辑：UC知道 时间：2024/06/22 10:58:16
final String str = "a aa, aa aaa aaa. aaaa aaaa aaaa aaaa aaaa ";
Map map = new HashMap();
StringTokenizer token = new StringTokenizer(str.toUpperCase(), ",. ");
int count = 1;
while (token.hasMoreElements()) {
String str2 = token.nextToken();
if(map.containsKey(str2)){
map.put(str2,count++);
}else{
map.put(str2,1);
}
}
Set set = map.keySet();
for (Iterator iter = set.iterator(); iter.hasNext();) {
String key = (String) iter.next();
String num = (String) map.get(key).toString();
System.out.println(key + ":" + num);
}
输出的结果是：AAAA:6
AA:1
AAA:2
A:1
如果还需排序该怎么办？
正确的结果是：AAAA:5
AA:2
AAA:2
A:1
Map map = new HashMap();
StringTokenizer token = new StringTokenizer(str.toUpperCase(), ",. ");
int count = 1;
while (token.hasMoreElements()) {
String str2 = token.nextToken();
if(map.containsKey(str2)){
map.put(str2,count++);
}else{
map.put(str2,1);
}
}
Set set = map.keySet();
for (Iterator iter = set.iterator(); iter.hasNext();) {
String key = (String) iter.next();
String num = (String) map.get(key).toString();
System.out.println(key + ":" + num);
}
输出的结果是：AAAA:6
AA:1
AAA:2
A:1
如果还需排序该怎么办？
正确的结果是：AAAA:5
AA:2
AAA:2
A:1
太抠了，才5分
Map<String,String> haha=new HashMap<String,String>();
List<String> order=new ArrayList<String>();
order.addAll(haha.keySet());
//这是按字母排序
Collections.sort(order);
//字母的反序
//Collections.sort(order,Collections.reverseOrder());
for(String key:order)
{
System.out.println(haha.get(key));
}