化简:(√ab-ab/a+√ab)÷(√ab-a/a-b)

来源:百度知道 编辑:UC知道 时间:2024/06/17 02:20:43
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[√ab - ab/(a+√ab)]÷( (√ab-a) / (a-b) )
= [√ab - ab/(√a(√a+√b))]÷( (√a(√b-√a)) / ((√a-√b)(√a+√b)) )
= [√ab - √a*b/(√a+√b)]÷( -√a / (√a+√b) )
= -[√ab - √a*b/(√a+√b)] /√a * (√a+√b)
= -[√b - b/(√a+√b)] * (√a+√b)
= -[√b(√a+√b) - b]
= -[√ab + b - b]
= -√ab

(√ab-ab)/(a+√ab)÷(√ab-a)/(a-b) ,这样吧!

原式=(√ab-ab)/(a+√ab)*(a-b) /(√ab-a)

=(√ab-ab)(a-b)/ab-a^2
=-(√ab-ab)/a
=b-√(b/a)