计算题一只

来源：百度知道 编辑：UC知道 时间：2024/05/30 19:13:28
(2a^2+3a+2)/(a+1)-(a^2-a-5)/(a+2)-(3a-4a-5)/(a-2)+(2a^2-8a+5)/(a-3)=(2a^2+2a+a+1+1)/(a+1)-(a^2+2a-3a-6+1)/(a+2)``````
后面怎么算```

4个式子全部用长除法分离系数得:
2a+1/(a+1)-a+3-1/(a+2)-3a-2+1/(a-2)-1/(a-3)+2a-2
=1/(a+1)-1/(a+2)+1/(a-2)-1/(a-3)
这个最简了

(2a^2+3a+2)/(a+1)-(a^2-a-5)/(a+2)-(3a^2-4a-5)/(a-2)+(2a^2-8a+5)/(a-3)
＝[2(a+1)^2-a]/(a+1)-[(a+2)^2-5a-9]/(a+2)-[3(a-2)^2+8a-17]/(a-2)+〔2(a-3)^2+4a-13〕/(a-3)
＝2(a+1)-(a+1-1)/(a+1)-(a+2)+(5a+10-1)/(a+2)-3(a-2)-(8a-16-1)/(a-2)+2(a-3)+(4a-12-1)/(a-3)
=2(a+1)-1+1/(a+1)-(a+2)+5-1/(a+2)- 3(a-2)-8+1/(a-2)+2(a-3)+4-1/(a-3)
=2+1/(a+1)-1/(a+2)+1/(a-2)-1/(a-3)