在 VC++ 6.0 中怎样使用 _itow 函数 !~??????>..

你好：
将整型数转换为字符串为:
wchar_t * _itow( int value, wchar_t *string, int radix );
一个小例子：
#include <iostream>
using namespace std;
int main( void )
{

wchar_t buffer[20];
int i = 45;

_itow( i, buffer, 10 );
cout<<buffer;
return 0;

}

Example

/* ITOA.C: This program converts integers of various
* sizes to strings in various radixes.
*/

#include <stdlib.h>
#include <stdio.h>

void main( void )
{
char buffer[20];
int i = 3445;
long l = -344115L;
unsigned long ul = 1234567890UL;

_itoa( i, buffer, 10 );
printf( "String of integer %d (radix 10): %s\n", i, buffer );
_itoa( i, buffer, 16 );
printf( "String of integer %d (radix 16): 0x%s\n", i, buffer );
_itoa( i, buffer, 2 );
printf( "String of intege