用matlab中的最小二乘法拟合指数函

来源：百度知道 编辑：UC知道 时间：2024/06/09 03:38:40
x=[0.0712,0.0803,0.0264,0.0081,0.0242,0.0464,0.0247,0.0037,0.0036];
y=[0.1436,0.1495,0.1320,0.0424,0.0662,0.0439,0.0178,0.0188,0.0094];
拟合一个月＝1－exp(x/a)^2的函数 急用 最好上机实践下 急用 有追加 谢谢

y-1=exp(x/a)^2
两边取对数，化成线性拟和
然后polyfit

x=[0.0712,0.0803,0.0264,0.0081,0.0242,0.0464,0.0247,0.0037,0.0036];
y=[0.1436,0.1495,0.1320,0.0424,0.0662,0.0439,0.0178,0.0188,0.0094];
b0=[1];
[b,R,J]=nlinfit(x,y,'fun',b0);
bi=nlparci(b,R,J);
b,

function y=fun(b,x)
y=1-exp(x/b)^2

x=[0.0712,0.0803,0.0264,0.0081,0.0242,0.0464,0.0247,0.0037,0.0036];
y=[0.1436,0.1495,0.1320,0.0424,0.0662,0.0439,0.0178,0.0188,0.0094];
b0=[1];
[b,R,J]=nlinfit(x,y,'fun',b0);
bi=nlparci(b,R,J);
b,bi