一条应用题怎么算?

解：设甲种布为X，乙种布为Y，丙中布为Z。
X+Y+Z
―――― = 0.45 ⑴,
3

X – Z = 0.08 ⑵,

Y – Z = 0.04 ⑶

由⑴式，⑵式，⑶式得⑷式，⑸式，⑹式

X + Y + Z = 0.45×3 → X + Y + Z = 1.35 ⑷

X = 0.08 + Z ⑸ ,

Y = 0.04 + Z ⑹

把⑸式，⑹式带入⑷式

(0.08 + Z) + (0.04 + Z) + Z = 1.35

0.08 + Z + 0.04 + Z + Z = 1.35

3Z = 1.35 – 0.12

3Z = 1.23

Z = 0.41

∴ X = 0.49

Y = 0.45

答: 甲种布为0.49元，乙种布为0.45元，丙中布为0.41元。

甲0.49元 乙0.45元 丙0.41元

甲+乙+丙=0.45*3
甲-丙=0.08
乙-丙=0.04
解方程得：甲=0.49
乙=0.45
丙=0.41

0.45+0.08=0.53

x+y+z=0.45*3````````````````````````1
x-z=0.08````````````````````````````2
y-z=0.04````````````````````````````3
解得x=0.41
y=0.45
z=0.49