计算(-2/3)-(+1/2)-(-5/6)-(+1/3)-(+1又1/2)
来源:百度知道 编辑:UC知道 时间:2024/06/05 01:02:16
要过程得数
(-2/3)-(+1/2)-(-5/6)-(+1/3)-(+1又1/2)
=[(-2/3)-(+1/3)]-[(+1/2)-(1又1/2)]-(-5/6)
=-1-1+5/6
=2又5/6
(-2/3)-(+1/2)-(-5/6)-(+1/3)-(+1又1/2)
=-2/3-1/2+5/6-1/3-(+1又1/2)
=(-2/3-1/3)+5/6+(-1/2-1又1/2)
=-1+5/6-2
=-3+5/6
=-(2又6/6-5/6)
=-2又1/6
解:=(-4/6)-(+3/6)-(-5/6)-(+1又3/6)
=(-4/6)-(3/6)+(5/6)-(9/6)
=(-11/6)
晕,问问大人不就行了
解:原式=(-2/3)-(+1/2)-(-5/6)-(+1/3)-(+1又1/2)
=[(-2/3)-(+1/3)]-[(+1/2)-(1又1/2)]-(-5/6)
=-1-1+5/6
=2又5/6
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