UC知道200分C++编程问题！
来源：百度知道 编辑：UC知道 时间：2024/06/06 01:50:47
是一个英文的题目，大意是要求做一个程序能够完成类似于手机键盘输入模块，按1次2输出a，连续按2次2输出b，然后还有些其他的要求。英文附在下面，多谢各位~~~
The diagram below shows the layout of a mobile phone keypad. Each key represents 3-4 lowercase letters and the digit associates with the key itself. To display a letter or a digit, a sequence of keystrokes is required. The table next to the keypad gives a few examples on how sms is produced by pressing the keys. Note that depending on the number of times a key is being pressed, there are more than one ways to display a letter or a digit. As for other keys in this keypad, key 0 produces a space in the sms, key 1 produce the digit '1', key * marks the end of the keystrokes, and the key # does not have any effect in the generation of sms. Keystrokes from user sms displayed (italics are comments, not the actual display)
2 a
22 b
222 c
2222 2
222222 b
888888888888 8
0
The diagram below shows the layout of a mobile phone keypad. Each key represents 3-4 lowercase letters and the digit associates with the key itself. To display a letter or a digit, a sequence of keystrokes is required. The table next to the keypad gives a few examples on how sms is produced by pressing the keys. Note that depending on the number of times a key is being pressed, there are more than one ways to display a letter or a digit. As for other keys in this keypad, key 0 produces a space in the sms, key 1 produce the digit '1', key * marks the end of the keystrokes, and the key # does not have any effect in the generation of sms. Keystrokes from user sms displayed (italics are comments, not the actual display)
2 a
22 b
222 c
2222 2
222222 b
888888888888 8
0
这道题有两种理解啊，一种是时间等待，另一种是输入-。
两种方案我都给你发到邮箱里去了，查收。
拿分，走人。
这个不难吧？？
你要什么样的程序？
win32 还是控制台？
这个可能需要设置定时器~定时器不是C++标准里的东西，不知道可以不。
不用定时器就得用多线程。很简单的。
我英文学得不好。
你把这段话翻译成中文发给我，还要说清楚是要窗口程序还是控制台程序，我写了给你。
我邮箱：
zzzhiv@126.com
太简单了。
#include <stdio.h>
#include <conio.h>
#include <windows.h>
void main()
{
int chr,old=0,times;
while((chr=getch())!='*')
{
if(chr=='#')
{
continue;
}
else if(chr=='1')
{
times=0;
old=chr;
printf("%c",chr);
}
else if(chr=='2')
{
const char c2[]={'a','b','c','2'};
if(old!=chr)
{
old=chr;
times=0;
printf("%c",c2[times]);
}
else
{
times=(times+