1/1×3+1/3×5+1/5×7+……+1/99×101
来源:百度知道 编辑:UC知道 时间:2024/05/22 12:34:07
1/1×3+1/3×5+1/5×7+……+1/99×101
=(1/2)×(1-1/3)+(1/2)×(1/3-1/5)+(1/2)×(1/5-1/7)+...+(1/2)×(1/99-1/101)
=(1/2)×[1-1/3+1/3-1/5+1/5-1/7+...+1/99-1/101]
=(1/2)×(1-1/101)
=(1/2)×(100/101)
=50/101
上式等于0.5*[(1/1-1/3)+(1/3-1/5)……+(1/99-1/101)]中间的每个数都可以和后一项抵消,所以结果为0.5*(1/1-1/101)=50/101
=(1-1/3+1/3-1/5+1/5-1/7.....-1/99+1/99-1/101)/2
=(1-1/101)/2
=50/101
1+1/2+1/3+.......+1/n=?
1+1/2+1/3+1/4...+1/n=?
1-1/3-1/5+1/3-1/5-1/7+1/5-1/7-1/9……+1/2003-1/2005-1/2007
1+1/2+1/3+1/4+1/5+1/6+1/7+1/8+......+1/100 = ?
(1-1/2)+(1/2-1/3)+(1/3-1/4)+..(1/2001-1/2002) 1/1x2+1/2x3+1/3x4+..+1/2001x2002
1×1/2+2×1/3+3×1/4+4×1/5+5×1/6+……98×1/99+99×1/100
1+1/(1+2)+1/(1+2+3)+…+1/(1+2+3+…+n)
1+1/(1+2) 1/(1+2+3)……+1/(1+2+3……+100)
1/1×2×3+1/2×3×4+1/3×4×5···+1/98×99×100
(1+1/2)(1+1/3+(1+1/4)……(1+1/100)/(1-1/2)(1-1/3)(1-1/4)……(1-1/100)