二进制与十进制的几道题（貌似很简单）

1 101
2 1101
3 10111
4 10000
都是用二进制表示的

这上面几位...258299054第3题算错了.1楼的那位,你算的是什么东西我怎么一点都看不懂....
1. 32+8+4+1 / 8+1 =45/9=5
2. 64+1 / 4+1 =65/5=13
3. 64+4+1 / 2+1 =69/3=23
4. 128+32+16+4 / 8+2+1 =180/11=??? 这道感觉有问题 如果是(1010)2就能算出整数了.

⑴ (101101)2÷(1001)2
=(2^5+2^3+2^2+1)/(2^3+1)
=(32+8+4+1)/(8+1)
=45/9
=5
=(2^2+1)
=(101)2
⑵ (1000001)2÷(101)2
=(2^6+1)/(2^2+1)
=(64+1)/(4+1)
=65/5
=13
=(2^3+2^2+1)
=(1101)2
⑶ (1000101)2÷(11)2
=(2^6+2^2+1)/(2^1+1)
=(64+4+1)/3
=69/3
=23
=(2^4+2^2+2^1+1)
=(10111)2
⑷ (10110100)2÷(1011)2
=(2^7+2^5+2^4+2^2)/(2^3+2^1+1)
=(128+32+16+4)/(8+2+1)
=180/11

⑴ (101101)2÷(1001)2
2进制转10进制
用8421码转换
1*2^0+0*2^1+1*2^2+1*2^3+0*2^4+1*2^5=45
1*2^0+0*2^1+0*2^2+1*2^3=9
45/9=5

⑵ (1000001)2÷(101)2
(1000001)=1*2^0+0*2^1+0*2^3+0*2^4+0*2^5+1*2^6=65