简便计算,就一道题

来源:百度知道 编辑:UC知道 时间:2024/06/14 02:42:18
(1-1/2+1/3-1/4+1/5-…+1/2007-1/2008)/(1/1005+1/1006+1/1007+…1/2007+1/2008)

(1-1/2+1/3-1/4+1/5-…+1/2007-1/2008)/(1/1005+1/1006+1/1007+…1/2007+1/2008)
=[1-(1-1/2)+(1/2-1/3)+(1/3-1/4)……+(1/2007-1/2008)]/[1/1005+(1/1005-1/1006)+(1/1006-1/1007)+……+(1/2007-1/2008)]
=(1/2008)/(1/2008)=1
又让我回想起了高中时代啊,呵呵……祝你学习进步哦!

1