初一数学,先化简,再求其值

来源:百度知道 编辑:UC知道 时间:2024/06/01 16:50:17
(1)x^3-x^2y+xy^2+yx^2-y^2x+y^3,其中x=1又1/2,y=-1又1/3。
(2)x^2yz-x^4+1/2x^2y^2-1/6x^2y^2+x^4-1/2x^2y^2,其中x=-1,y=-2,x=-1/3(大家尽可能把过程写详细啊)
不好意思啊,后面的是z=-1/3

x^3-x^2y+xy^2+yx^2-y^2x+y^3
=x(x^2-xy+y^2)+y(x^2-yx+y^2)
=(x+y)(x^2-xy+y^2)
=(x+y)[(x-y)^2+xy]
=(1/6)*[(17/6)^2-2]
=217/216
x+y=3/2+(-4/3)=1/6
x-y=3/2-(-4/3)=17/6
xy=3/2*(-4/3)=-2

x^2yz-x^4+1/2x^2y^2-1/6x^2y^2+x^4-1/2x^2y^2
=x^2yz-1/6x^2y^2
=x^2y(z-1/6y)
=1*(-2)*(-1/3+1/3)=0

(1)原式=x^3+y^3
=27/8+(-64/27)=217/216

(2)原式=(x^2)y(z-1/6y)
=1*(-2)*(-1/3+1/3)=0

X后是什么号啊