c语言编程题，计算1×2×3＋3×4×5＋······＋99×100×101的值

这里用三种方法解决。只需要输入N的值就行了。上面这个题输入101就行了。

#include <stdio.h>

int main()
{
int n;
printf("please enter the number:(numbers only)\n");
scanf("%d",&n);
int i;
long fact;

fact=n;
for(i=1;i<n;i++)
{
fact*=i;
}
printf("The factorial of %d is %ld.\n",n,fact);

fact=n;
i=1;
while(i<n)
{
fact*=i;
i++;
}
printf("The factorial of %d is %ld.\n",n,fact);
fact=n;
i=1;
do{
fact*=i;
i++;
}while(i<n);
printf("The factorial of %d is %ld.\n",n,fact);

getchar();

}

已经调试过了，在GCC下面正确编译，在TC下面一定没有问题。

# include<stdio.h>
void main()
{
long value=0 , temp;
int i;
for(i=1 ; i<= 99 ; i+=2)
{temp=i*(i+1)*(i+2);
value+= temp;
}
printf("%ld",value);
}

这个很简单啊，用循环能搞定