化简 √(1-2sin10°cos10°) / sin10°-√(1-sin^210°)

来源:百度知道 编辑:UC知道 时间:2024/06/21 22:35:36
过程

√(1-2sin10°cos10°) / sin10°-√(1-sin^210°)
=√(sin10°-cos10°)^2/sin10°-cos10°
=-√2[sin(10°-45°)]/sin10°-cos10°
=(-1cos10°+sin10°)/sin10°-sin10°cos10°/sin10°
=....

哎呀...找不到笔了...应该就是这思路了...不好意思啊!!

=√(sin^210°-cos^210°)/sin10°-√(sin^210°+cos^210°-sin^210°)
=cos10-sin10/sin10-cos10
=-1