初二分解因式! 高分赏

来源:百度知道 编辑:UC知道 时间:2024/06/03 14:09:32
(1)xy²-x²y
(2)ma+mb+mc
(3)-2x²-12xy²+8xy^3
(4)2a(b+c)-3(b+c)
(5)2(m-n)²-(n-m)(m+n)
(6)x(x+y)(x-y)-x(x+y)²
(7)49(1-p)^3+2(p-1)²
(8)(a+b)²-4a²
(9)x^4-81x²y²
(10)x²(x-y)+y²(y-x)
(11)(a+b+c)²-(a-b-c)²
(12)m²+2m+1
(13)9x²-12x+4
(14)1-10x+25x²
(15)(m+n)²-6(m+n)+9

1,=xy(y-x)
2,=m(a+b+c)
3,=-2x(x+y^2-4y^3)
4,=(2a-3)(b+c)
5,=(m-n)(2m-2n-m-n)=(m-n)(m-3n)
6,=x(x+y)(x-y-x-y)=-2xy(x+y)
7,=(49-49p+2)(1-p)^2=(51-49p)(1-p)^2
8,=(a+b+2a)(a+b-2a)=(3a+b)(b-a)
9,=(x^2+9xy)(x^2-9xy)=x^2(x+9y)(x-9y)
10,=(x-y)(x^2-y^2)=(x+y)(x-y)^2
11,=(a+b+c+a-b-c)(a+b+c-a+b+c)=4a(b+c)
12,=(m+1)^2
13,(3x-2)^2
14,=(1-5x)^2
15,=(m+n-3)^2

(1)xy²-x²y=xy(y-x)
(2)ma+mb+mc =m(a+b+c)
(3)-2x²-12xy²+8xy^3 =-2x(x+6y²-4y^3)
(4)2a(b+c)-3(b+c)=(2a-3)(b+c)
(5)2(m-n)²-(n-m)(m+n)=2(m-n)²+(m-n)(m+n)=(m-n)(2m-2n+m+n)=(m-n)(3m-n)
(6)x(x+y)(x-y)-x(x+y)²=x(x+y)(x-y-x-y)=-2xy(x+y)
(7)49(1-p)^3+2(p-1)²=49(1-p)^3+2(1-p)²=(1-p)²(49-49p+2)=(1-p)²(51-49p)
(8)(a+b)²-4a²=(a+b)²-(2a)²=(a+b+2a)(a+b-2a)=(3a+b)(b-a)
(9)x^4-81x²y²=x²[x²-(9y)²]=x²(x+9y)(x-9y)
(10)x²(x-