哪错了？MATLAB 解非线性规划的程序

来源：百度知道 编辑：UC知道 时间：2024/06/05 09:09:18
大家帮忙看看哪里出错了？是一个求非线性规划的程序
function f=myfun(u)
f=50*(abs(u(3))+abs(u(17))+abs(u(29)))+200*(abs(u(5))+abs(u(19))+abs(u(31)));
float u[1][37];
A=[0 0 1 0 0 0 0 -1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 1 0 0 0 0 -1 1 1 1 0 0 0 0 0 1 0 0 0 -1 -1 -1 1 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 1 0 0 0 0 -1 1 1 1 0 0 0 0 0 1 0 0 0 -1 -1 -1 1 0 0 0 0 1 0 0 1 -1 -1 1 0 0;
0 0 0 1 0 0 0 0 0 -1 0 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 1 0 0 0 0 0 -1 0 0 1 1 0 0 0 1 0 0 0 0 1 0 1 1 0 0 0 0 0 0 0 0 0 0 0 ;
0 0 0 1 0 0 0 0 0 -1 0 0 1 1 0 0 0 1 0 0 0 0 1 0 1 1 0 0 0 -1 0 -1 0 0 0 1 1;
-1 -1 -1 -1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
-1 -1 -1 -1 1 0 0 0 0 0 0 0 0 0 1 1 -1 -1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
-1 -1 -1 -1 1 0 0 0 0 0 0 0 0 0 -1 1 -1 -1 1 0 0 0 0 0 0 0 1 1 -1 1 1 0 0 0 0 0 0;
0 0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

先把下面语句保存为myfun.m
function [u,fval]=myfun
A=[0 0 1 0 0 0 0 -1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 1 0 0 0 0 -1 1 1 1 0 0 0 0 0 1 0 0 0 -1 -1 -1 1 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 1 0 0 0 0 -1 1 1 1 0 0 0 0 0 1 0 0 0 -1 -1 -1 1 0 0 0 0 1 0 0 1 -1 -1 1 0 0;
0 0 0 1 0 0 0 0 0 -1 0 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 1 0 0 0 0 0 -1 0 0 1 1 0 0 0 1 0 0 0 0 1 0 1 1 0 0 0 0 0 0 0 0 0 0 0 ;
0 0 0 1 0 0 0 0 0 -1 0 0 1 1 0 0 0 1 0 0 0 0 1 0 1 1 0 0 0 -1 0 -1 0 0 0 1 1;
-1 -1 -1 -1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
-1 -1 -1 -1 1 0 0 0 0 0 0 0 0 0 1 1 -1 -1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
-1 -1 -1 -1 1 0 0 0 0 0 0 0 0 0 -1 1 -1 -1 1 0 0 0 0 0 0 0 1 1 -1 1 1 0 0 0 0 0 0;
0 0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ;
0 0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ;
0 0 0 0 0 0 0