用配方法或者是开平方法解（1-x)²+5=5（x-1)

1-2x+x^2+5=5x-5整理得x^2-7x+11=0配方得（x-7/2)^2=5/4得x=7/2加减2分之根号下5

（1-x）2+5=5(x-1)
1-2x+x2+5=5x-5
x2-7x+11=0
x2-2*7/2x+49/4-5/4=0
(x-7/2)2=5/4
x-7/2=根号下5 除以2
x=7/2+根号下5 除以2
x=(7+根号下5)/2

(x-1)^2 - 5(x-1) +5 = 0;
设y=x-1;
y^2-5y+5 = 0;
(y-2)(y-3)=0;
y=2 or y=3;
x = 3or4;