初二数学问题，，【【分式的约分】】··追加++++++++++++

来源：百度知道 编辑：UC知道 时间：2024/06/12 04:43:56
(1)a³-4ab²/a³-4a²b+4ab²，其中a=-2,b=-0.5.

(2)1-4x^4/2x³+x

(3)x²y-2xy+y/y-x²y

要过程滴哈~好的答案一定追加，，多少都行，，大家来订！但不能超过150哈！

(1)(a^3-4ab^2)/(a^3-4a^2b+4ab^2)
=a(a^2-4b^2)/a(a^2-4ab+4b^2)
=[a(a-2b)(a+2b)]/a(a-2b)^2
=(a+2b)/(a-2b)
=[-2+2*(-0.5)]/[-2-2*(-0.5)]
=(-2-1)/(-2+1)
=3

(2)(1-4x^4)/(2x^3+x)
=(1-2x^2)(1+2x^2)/x(2x^2+1)
=(1-2x^2)/x

(3)(x^2y-2xy+y)/(y-x^2y)
=y(x^2-2x+1)/y(1-x^2)
=y(x-1)^2/y(1-x)(1+x)
=-(x-1)/(1+x)
=(1-x)(1+x)

(1)a³-4ab²/a³-4a²b+4ab²
=a(a²-4b²)/a(a²-4ab+4b²)
=(a+2b)(a-2b)/(a-2b)²
=(a+2b)/(a-2b)
=(-2-1)/(-2+1)
=3

(2)1-4x^4/2x³+x
=(1+2x²)(1-2x²)/x(2x²+1)
=(1-2x²)/x

(3)x²y-2xy+y/y-x²y
=y(x²-2x+1)/y(1-x²)
=(x-1)²/(1+x)(1-x)
=-(x-1)/(x+1)

(1)a³-4ab²/a³-4a²b+4ab²
=a(a²-4b²)/a(a²-4ab+4b²)
=(a+2b)(a-2b)/(a-2b)²
=(a+2b)/(a-2b)
=3

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