简单JAVA编程

来源：百度知道 编辑：UC知道 时间：2024/06/24 04:27:39
S=1+2+3+....+N. N是从命令行接受的整数!

public static void main(String args[]) throws Exception {
Scanner scan = new Scanner(System.in);
System.out.println("请输入一个正整数:");
int n = scan.nextInt();
int result = 0;
for(int i = 1;i<=n;i++) {
result += i;
}
System.out.println("结果为: "+i);
}

public static void main(String args[]) throws Exception {
Scanner scan = new Scanner(System.in);
System.out.println("请输入一个正整数:");
int n = scan.nextInt();
BigInteger result = BigInteger.valueOf(1);
for(int i = 1;i<=n;i++) {
result = result.multiply(BigInteger.valueOf(i));
}
System.out.println(result.toString());
}

System.out.println("请输入一个正整数:");
nt n = scan.nextInt();
BigInteger result = BigInteger.valueOf(1);
for(int i = 1;i<=n;i++) {
result = result.multiply(BigInteger.valueOf(i));
}