UC知道请高手看看下面的程序，怎么不对？
来源：百度知道 编辑：UC知道 时间：2024/06/18 09:02:52
string str2[10];
vector<double>Sample1；
vector<double>temp；
if(str2[1][0]=='+')
{
str2[1]="";
str2[1]="1";
for(i=2;i<4;i++)
{
temp=atof(str2[i]);
Sample1.push_back(temp);
}
}
错误显示：
E:\练习\string.cpp(50) : error C2664: 'atof' : cannot convert parameter 1 from 'class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> >' to 'const char *'
No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
E:\练习\string.cpp(51) : error C2664: 'push_back' : cannot convert parameter 1 from 'class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> >' to 'const double &'
Rea
vector<double>Sample1；
vector<double>temp；
if(str2[1][0]=='+')
{
str2[1]="";
str2[1]="1";
for(i=2;i<4;i++)
{
temp=atof(str2[i]);
Sample1.push_back(temp);
}
}
错误显示：
E:\练习\string.cpp(50) : error C2664: 'atof' : cannot convert parameter 1 from 'class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> >' to 'const char *'
No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
E:\练习\string.cpp(51) : error C2664: 'push_back' : cannot convert parameter 1 from 'class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> >' to 'const double &'
Rea
类型不对呀
temp=atof(str2[i]);
这面这句str2[i]返回的是string，而atof需要的参数是const char*，不能转换，atof的返回类型是浮点数，temp是vector，也不行。
Sample1.push_back(temp);
sample1是double的vector，怎么能添加一个temp这样一个vector类型的元素呢