分解因式哦,帮帮忙把!

2x^2+2x+1/2=2(x^2+x+1/4)=2(x+1/2)^2

(x^2+1)^2-4x(x^2+1)+4x^2=(x^2+1-2x)^2=(x-1)^4

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2x^2+2x+1/2
=1/2(4x^2+4x+1)
=1/2(2x+1)^2

(X^2+1)^2-4X(X^2+1)+4X^2
=(x^2+1-2x)^2
=(x-1)^4

2X^2+2X+2分之1
=2(x^2+x+1/4)
=2(x+1/2)^2

(X^2+1)^2-4X(X^2+1)+4X^2
=(x^2+1-2x)^2
=(x-1)^4

2X^2+2X+2分之1=(根号2*x+根号2/2)^2

(X^2+1)^2-4X(X^2+1)+4X^2=（x^2+1-2x）^2=[(x-1)^2]^2