任意输入一串字符（敲回车键结束输入）统计出其英文大写字母、英文小写字母、空格、数字和其它字符的个数

#include<stdio.h>
main(){
int i=0;
int m=0;
int n=0;
char c;
clrscr();
while((c=getchar())!='\n'){
if (65<=c&&c<=90) i++;
else if(97<=c&&c<=122) m++;
else if(48<=c&&c<=57) n++;

}
printf("da xie zi mu you %d ge,xiao xie zi mu you %d ge,shu zi you %d ge!",i,m,n);

}

程序测试成功！

#include <stdio.h>

void main()
{
char buff[1024];
int i,j,L;
int Ed=0,Ex=0,sp=0,digi=0,other=0;
printf("Enter one line\n");
fgets(&buff[0],1023,stdin);
L = strlen(buff);
for (i=0;i<L;i++){
if (buff[i] <= 'Z' && buff[i] >= 'A') Ed++;
else if (buff[i] <= 'z' && buff[i] >= 'a') Ex++;
else if (buff[i] == ' ') sp++;
else if (buff[i] <= '9' && buff[i] >= '0') digi++;
else other++;
};
printf(&