输出由*组成的金字塔，用C语言怎么编

给，已经编译运行确认：
#include<conio.h>
#include<stdio.h>

int main()
{
int i,j,n;

printf("please input n:\n");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(j=1;j<=n-i;j++)printf(" ");
for(j=1;j<=2*i-1;j++)printf("*");
printf("\n");
}

getch();
return 1;
}

#include <stdio.h>
#include <stdlib.h>

void main ()
{
int i,j,k,m,n,size;

printf ("input size: ");
scanf ("%d",&size);
if (size <=0||size%2==0)
{
printf ("thr size is error!\n");
exit (-1);
}
for (i=1;i<=size;i++)
{
n=(i<=(size+1)/2) ? i : size-i+1;
n=2*n-1;
m=(size-n)/2+15;
for (k=1;k<=m;k++)
printf (" ");
for (j=1;j<=n;j++)
printf ("*&quo