UC知道Servlet接收页面参数的问题
来源：百度知道 编辑：UC知道 时间：2024/06/25 08:33:34
为什么我在http://localhost:8080/TomcatProjecy1/页面中输入了N1和N2的值,点提交后的页面却什么都没有?
index.jsp中的代码:
<%@ page language="java" import="java.util.*" pageEncoding="GB18030"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'index.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content
index.jsp中的代码:
<%@ page language="java" import="java.util.*" pageEncoding="GB18030"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'index.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content
在servlet端应该以request.getParameter(String param);方法来获取前台提交的表单参数。你的this.getServletConfig().getInitParameterNames()方法会返回servlet的配置信息的名字的枚举。
在servlet中的doget（）方法中，直接
String n1 = request.getInitParameter("N1");
String n2 = request.getInitParameter("N2");
System.out.println("n1="+n1);
System.out.println("n2="+n2);