在VB中，怎么用MID函数，抓取文本框中的数据

Dim a(0 To 100) As String, i, j As Long
For i = 1 To Len(Text1) Step 2 '循环取出字符
If i <= 100 Then a((i - 1) / 2) = Mid(Text1, i, 2) 'Mid(原字符，从什么位置开始读取，读取字符的个数)
Next

For j = 0 To (i - 1) / 2 - 1 '显示到窗口
Print a(j)
Next
Print i
Print Len(Text1)
'结果为a(0)=12 a(1)=34 a(2)=56 a(3)=77 a(4)=89，正是你要的结果

str1="1234567789"
for i = 1 to len(str1) step 2
print mid(str1,i,2)
next i

Private Sub Command1_Click()
strText = "12345677891"
Dim a(0 To 100) As Byte
For i = 0 To ((Len(strText) - 1) / 2)
a(i) = Val(Mid(strText, i * 2 + 1, 2))
Next
End Sub

Private Sub Command1_Click()
Dim I As Long, J as long, a(0 To 100) As Byte
For I = 1 To Len(Text1.Text) Step 2
a(j) = Val(Mid(Text1.Text, I, 2))
j=j+1
Next
End Sub
Private Sub Form_Load()
Text1.Text = "12345677891"
En