编程答案是什么

来源:百度知道 编辑:UC知道 时间:2024/05/22 17:21:03
(1)Write an expression that retrieves the value in the location immediately after the location pointed to by the integer pointer variable ip .
(2)Assume the availability of a function called fact. The function receives an int argument and returns an int value. If the argument is one or smaller, it returns the integer value one. Otherwise it returns the product of all the integers from one to its argument.

So the value of fact(4) is 1*2*3*4 and the value of fact(10) is 1*2*3*4*5*6*7*8*9*10.
Assume further that the variable k has been declared and initialized to a positive integer.
Assume further that the variable x has been declared as an integer type.
Write a statement that assigns x the value k*(k-1)*(k-2)*...*3*2*1 by calling the fact function and multiplying its return value by k.

Note: your solution must include multiplying fact's return value by k here.
(3)Write the definition of a function minMax that has five param

( 1 )写一篇表达检索中的值的位置的位置后立即指出的整数指针变量的IP 。
( 2 )承担的可用性功能要求的事实。功能得到一个int参数并返回一个int值。如果该参数是一个或小,它返回一个整数值。否则,它将返回的产物,所有的整数一至其论点。

所以实际上的价值( 4 ) 1 * 2 * 3 * 4和价值的事实( 10 )是1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 * 10 。
承担进一步变量k已宣布和初始化为一个正整数。
承担进一步变量x已被宣布为整数类型。
写一份声明中指定第十价值k * ( K - 1的) * (的K - 2 )*...* 3 * 2 * 1致电事实乘以其功能和返回值的K.

注:您的解决办法必须包括乘以事实上的返回值用K这里。
( 3 )收件的定义函数最小最大的有5个参数。前三个参数是整数。在过去两年设置的功能,最大和最小的价值,前三个参数。

该函数不返回一个值。

该功能可用于如下:

诠释1 = 31 ,乙= 5和c = 19 ,大,小;
最小最大(甲,乙,丙,与大,小) ;
/ *大,现在31 * /
/ *小现在是5 * /

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以上英文翻译由 爱词霸在线翻译提供
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