求高人注释一段asp验证码的程序,由于很着急没多少分,求高人帮帮忙!!!

来源:百度知道 编辑:UC知道 时间:2024/05/18 15:54:44
<%
Option Explicit
NumCode
Function NumCode()
Response.Expires = -1
Response.AddHeader "Pragma","no-cache"
Response.AddHeader "cache-ctrol","no-cache"
dim zNum,i,j
dim Ados,Ados1
Randomize timer
zNum = cint(8999*Rnd+1000)
Session("GetCode") = zNum
dim zimg(4),NStr
NStr=cstr(zNum)
For i=0 to 3
zimg(i)=cint(mid(NStr,i+1,1))
Next
dim Pos
set Ados=Server.CreateObject("Adodb.Stream")
Ados.Mode=3
Ados.Type=1
Ados.Open
set Ados1=Server.CreateObject("Adodb.Stream")
Ados1.Mode=3
Ados1.Type=1
Ados1.Open
Ados.LoadFromFile(Server.mappath("body.Fix"))
Ados1.write Ados.read(1280)
for i=0 to 3
Ados.Position=(9-zimg(i))*320
Ados1.Position=i*320
Ados1.write ados.read(320)
next
Ados.LoadFromFile(Server.mappath("head.fix"))
Pos=lenb(Ados.read())

好像没理解你,不输入验证码或者为空,则通过?

<%
Option Explicit
NumCode
Function NumCode()
Response.Expires = -1
Response.AddHeader "Pragma","no-cache"
Response.AddHeader "cache-ctrol","no-cache"
dim zNum,i,j
dim Ados,Ados1
Randomize timer
zNum = cint(8999*Rnd+1000)
'Session("GetCode") = zNum
dim zimg(4),NStr
NStr=cstr(zNum)
For i=0 to 3
zimg(i)=cint(mid(NStr,i+1,1))
Next
dim Pos
set Ados=Server.CreateObject("Adodb.Stream")
Ados.Mode=3
Ados.Type=1
Ados.Open
set Ados1=Server.CreateObject("Adodb.Stream")
Ados1.Mode=3
Ados1.Type=1
Ados1.Open
Ados.LoadFromFile(Server.mappath("body.Fix"))
Ados1.write Ados.read(1280)
for i=0 to 3
Ados.Position=(9-zimg(i))*320
Ados1.Position=i*320
Ados1.write ados.read(320)
next
Ados.LoadFromFile(Server.mappath("h