UC知道杭电acm1008，谁帮我看看我错在哪里啊？？？
来源：百度知道 编辑：UC知道 时间：2024/06/04 02:39:37
一直是wrong answer，谁帮我看看，谢了！
题目是这样：
Problem Description
The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.
For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.
Input
There are multiple test cases. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100. A test case with N = 0 denotes the end of input. This test case is not to be processed.
Output
Print the total time on a single line for each test case.
Sam
题目是这样：
Problem Description
The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.
For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.
Input
There are multiple test cases. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100. A test case with N = 0 denotes the end of input. This test case is not to be processed.
Output
Print the total time on a single line for each test case.
Sam
我不知道为什么你要下这么复杂，先贴上我以前AC的代码，加了点注释，再慢慢看你的。。
#include <stdio.h>
int main(){
int a,b,n,t;
while(scanf("%d",&n)!=EOF&&n){
t=0;b=0;
t+=n*5;//停的总时间累加起来
while(n--){
scanf("%d",&a);
if(a>b)t+=6*(a-b);//与前次比若上升
else if(a<b)t+=4*(b-a);//与前次比若下降
b=a;
}
printf("%d\n",t);
}
return 0;
}
给你个建议 ，重写一次