求因式分解题答案，急

x（2）＋6x＋8
=x^2+6x+8
=(x+2)(x+4)

8a(3)-b(3)
=(2a-b)(4a^2+2ab+b^2)

x(2)-2x-1
=x^2-2x+1-2
=(x-1)^2-2
=(x-1+√2)(x-1-√2)

4（x-y+1)+y(y-2x)
=4x-4y+4+y^2-2xy
=(y^2-4y+4)-2x(2-y)
=(y-2)^2+2x(y-2)
=(y-2)(2x+y-2)

a(3)+1
=(a+1)(a^2-a+1)

4x(4)-13x(2)+9
=(4x^2-9)(x^2-1)
=(2x+3)(2x-3)(x+1)(x-1)

x(2)+x-(a(2)-a)
=x^2-a^2+x+a
=(x+a)(x-a)+x+a
=(x+a)(x-a+1)

3x(2)+4xy-y(2)
=3x^2+4xy-y^2
= 3(x^2+ xy*4/3 - y^2*1/3)
= 3[(x^2+ 2*2/3 *xy +4/9y^2) - y^2/3- 4/9y^2]
= 3[(x+2/3y)^2 - 7/9 y^2]
=3(x+2/3y +√7/3y)(x+2/3y - √7/3y)
= 3[x+(2+√7)/3y][x+(2-√7)/3y]

(x(2)-2x)(2)-7(x(2)-2x)+12
=(x^2-2x)^2-7(x^2-2x)+12
=(x^2-2x-3)(x^2-2x-4)
=(x-3)(x+1)(x^2-2x-4)
=(x-3)(x+1)(x^2-2x+1-5)
=(x-3)(x+1)[(x-1)^2-5]
=(x-3)(x+1)(x-1+√5)(x-1-√5)

3x(2)+5xy-2y(2)+x+9y-4
=3x^2+5xy-2y^2+x+9y-