解答高一数学题，比较简单

（1）1/sin10`-（√3）/cos10`
=(cos10°-(根号3)sin10°)/(sin10°×cos10°)
=2(1/2 cos10°- (根号3)/2 sin10°))/(sin10°×cos10°
=2(sin30°cos10°-cos30°sin10°)/(sin10°×cos10°)
=2sin20°/(sin10°×cos10°)
=4sin20°/(2sin10°×cos10°)
=4sin20°/sin20°
=4

（2）sin40°(tan10°-根号3)
=sin40*sin10/cos10-根号3*sin40
=sin40*cos80/cos10-根号3*sin40
=sin40*cos80/2sin40*cos40-根号3*sin40
=(1/2)*cos80/cos40-根号3*sin40
=[(1/2)*cos80-根号3sin40*sin40]/cos40
=[(1/2)cos80-根号3/2*sin80]/cos40
=(sin30*cos80-cos30*sin80)/cos40
=sin(30-80)/cos40
=-sin50/cos40
=-1

（3）tan70×cos10×(√3tan20-1)
=tan70×cos10×(tan60×tan20-1)
=tan70×cos10×[(sin60×sin20/cos60×cos20)-1]
=tan70×cos10×(sin60×sin20-cos60×cos20)/(cos60×cos20)
=tan70×cos10×[-cos(60+20)]/(cos60 ×cos20)
=-tan70×cos10×cos80/(cos60×cos20)
=-tan70×cos10×sin10/(cos60×cos20)
=-(sin70/cos70)×(1/2)×sin20/(cos60×cos20)
=-(cos20/sin20)×sin20/(