对数化简

(lg3+2/5lg9+3/5lg√27-lg√3)/(lg81-lg27)
=(lg3+4/5lg3+(3/2)(3/5)lg3-1/2lg3)/(4lg-3lg3)
=lg3[1+4/5+(3/2)(3/5)-1/2]/lg3
=1+4/5+9/10-1/2
=(10+8+9-5)/10
=22/10
=11/5

（lg3+2/5lg9+3/5lg根号27-lg根号3）除以lg81-lg27
=2.2
一步一步算，没难度的