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来源：百度知道 编辑：UC知道 时间：2024/05/16 08:55:05
X^2=(3X+1)^2

1/X-2+3=1-X/2-X

(1+3/X-1)÷X+2/X^2-1

X^2=(3X+1)^2
X=(3X+1)
x=-1/2

1/X-2+3=1-X/2-X
1+3(X-2)=-(1-X)
3x-5=x-1
2x=4
x=2

(1+3/X-1)÷X+2/X^2-1
=(1+3/(X-1)*(X-1)(x+1)/(X+2)
=(X-1)(x+1)/(X+2)+3(x+1)/(X+2)
=[(X^2+3x+2]/(X+2)
=x+1

1,x=3x+1
-2x=1
x=-1/2

-x=3x+1
-4x=1
x=-1/4

2,1+3x-6=x-2+x
x=3

3,(1+3/X-1)÷X+2/X^2-1
=4/(x-1)*(x^2-1)/(x+1)
=4

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X^2=(3X+1)^2
解x=-1/4,x=-1/2

1/X-2+3=1-X/2-X
解x=2

(1+3/X-1)÷X+2/X^2-1 题目何意