(sin50(1+根号3*tan10)-cos20)/cos80根号(1-cos20)
来源:百度知道 编辑:UC知道 时间:2024/05/10 18:47:29
(sin50°(1+√3*tan10°)-cos20°)/(cos80°*√(1-cos20°))
=(sin50°(1+√3*sin10°/cos10°)-cos20°)/(cos80°*√(1-cos20°))
=(sin50°((cos10°+√3*sin10°)/cos10°)-cos20°)/(cos80°*√(2(sin10°)^2))
=(sin50°((1/2)cos10°+(√3/2)*sin10°)/((1/2)*cos10°)-cos20°)/(cos80°*√(2(sin10°)^2))
=(sin50°(sin30°*cos10°+cos30°*sin10°)/(1/2)*cos10°-cos20°)/((√2)cos80°*sin10°)
=(sin50°*sin40°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=(sin50°*cos50°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)sin100°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)sin80°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)cos10/(1/2)*cos10°-cos20°)/((√2)sin10°sin10°)
=(1-cos20°)/((√2)sin10°sin10°)
=2(sin20°)^2/(√2)(sin20°)^2
=2/√2
=√2
sin50°(1+根号3×tan10°)的值??
sin50度乘以(1+根号3乘以tan10度)等于?
sin50(1 根号3乘以tan10)要过程
求值sin50度(1+根号3tan1o度)=
((sin40+sin50(1+根号3*tan10))/sin70*根号(1+cos40)
〔2sin50°+sin10°(1+根号3再乘tan10°)〕*根号下2*sin80°的平方〕
sin50*(1+√3*tan 10)
大家帮帮忙,一道数学题,请写出详细过程。计算:[sin50\'+cos40\'(1+根号3tan10\')]sec20平方
sin50度,带根号的准确值是多少?
根号x=根号3-1(1不带根号)