求解？题目在图里

这题目出的，真是变态。
一点一点来：
(1/4)^(-1/2)=(1/4)^(-1)^(1/2)=4^(1/2)=2
[4ab^(-1)]^(3/2)=4^(3/2)*a^(3/2)*b^(-3/2)=8a^(3/2)*b^(-3/2)
0.1^(-2)*[a^(-3)b^(-3)]^(1/2)=100a^(-3/2)*b^(-3/2)
所以[4ab^(-1)]^(3/2)/0.1^(-2)*[a^(-3)b^(-3)]^(1/2)
=[8a^(3/2)*b^(-3/2)]/[100a^(-3/2)*b^(-3/2)]
=2a^3/25
所以(1/4)^(-1/2)*[4ab^(-1)]^(3/2)/0.1^(-2)*[a^(-3)b^(-3)]^(1/2)
=2*2a^3/25
=4a^3/25