UC知道java applet时钟程序时针坐标的算法怎么回事弄不懂了，大侠帮忙
来源：百度知道 编辑：UC知道 时间：2024/06/26 01:01:27
// Paint is the main part of the program
public void update(Graphics g) {
int xh, yh, xm, ym, xs, ys;
int s = 0, m = 10, h = 10;
String today;
currentDate = new Date();
formatter.applyPattern("s");
try {
s = Integer.parseInt(formatter.format(currentDate));
} catch (NumberFormatException n) {
s = 0;
}
formatter.applyPattern("m");
try {
m = Integer.parseInt(formatter.format(currentDate));
} catch (NumberFormatException n) {
m = 10;
}
formatter.applyPattern("h");
try {
h = Integer.parseInt(formatter.format(currentDate));
} catch (NumberFormatException n) {
h = 10;
}
// Set position of the ends of the
public void update(Graphics g) {
int xh, yh, xm, ym, xs, ys;
int s = 0, m = 10, h = 10;
String today;
currentDate = new Date();
formatter.applyPattern("s");
try {
s = Integer.parseInt(formatter.format(currentDate));
} catch (NumberFormatException n) {
s = 0;
}
formatter.applyPattern("m");
try {
m = Integer.parseInt(formatter.format(currentDate));
} catch (NumberFormatException n) {
m = 10;
}
formatter.applyPattern("h");
try {
h = Integer.parseInt(formatter.format(currentDate));
} catch (NumberFormatException n) {
h = 10;
}
// Set position of the ends of the
他这个没用圆，用了三角函数。十二个小时是360°，一个小时就是30°。那么假设从12：0：0算起，现在若是h:m:s那么应该时针应该转过了(h+m/60+s/360)*30，等于h*30+m/2+s/12,只不过s/12太小了没有算，然后乘于π/180是把他转换成弧度制，再减去π/2转换成它的余角，然后cos*30，30应该是时针的长度吧，余弦值乘于斜边得到时针水平方向的长度，加上中心x坐标，得到时针x坐标，在具体就不好描述了，你学过几何吧，很简单的，画个图自己试试