类比｛an｝为等差数列，则有bn=(a1+a2+a3+…+an)/n为等差数列，若｛cn｝为等比数列，则dn=？也为等比数列

Dn=(C1×C2×C3×……×Cn)^(1/n)成等比数列

Bn=Sn/n=(nA1+(1/2)n(n-1)d)/n=A1+(n-1)(d/2)
Bn是以A1为首项，d/2为公差的等差数列。

类比Dn=(C1×C1×q^1×C1×q^2×……×C1×q^(n-1))^(1/n)
=(C1^n×q^(n(n-1)/2))^(1/n)
=C1×[q^(1/2)]^(n-1)
Dn是以C1为首项，q^(1/2)为公比的等比数列。

dn=(C1×C2×C3×……×Cn)^(1/n)