初一整式(很简单!)能做多少是多少 求速度!
来源:百度知道 编辑:UC知道 时间:2024/06/22 20:52:56
4x³y³(四分之三x²y²)(-四分之一x²y)³·16xy²,其中x=0.4,y=-2.5
2xy·(-2x²y²)·(-3x³y³)
(-0.125)^8·2^25
已知x^n=5,y^n=3 求(x²y³)^n
(-三分之二ax^n)²+三分之二a²(-x²)^n (n为正整数)
(3m²n)·(三分之二m²n²)-(-10m)·m³n³
2xy·(-2x²y²)·(-3x³y³)
(-0.125)^8·2^25
已知x^n=5,y^n=3 求(x²y³)^n
(-三分之二ax^n)²+三分之二a²(-x²)^n (n为正整数)
(3m²n)·(三分之二m²n²)-(-10m)·m³n³
4x³y³((3/4)x²y²)(-(x²y)/4)³*16xy²,其中x=0.4,y=-2.5
4x³y³((3/4)x²y²)(-(x²y)/4)³*16xy²
=(3*x^5y^5)(-(x²y))³*16xy²/64
=-(3*x^5y^5)(x^6y^3)*xy²/4
=-(3*x^11y^8)*xy²/4
=-(3*x^12y^10)/4
=-(3*(0.4)^12*(-2.5)^10)/4
=-0.12
2xy*(-2x²y²)*(-3x³y³)
=12*x^6*y^6
(-0.125)^8*2^25
=(-0.125*2^3)^8*2
=2
已知x^n=5,y^n=3 求(x²y³)^n
(x²y³)^n
=(x^n)^2*(y^n)^3
=5^2*3^3
=25*27
=675
(-三分之二ax^n)²+三分之二a²(-x²)^n
(-(2/3)ax^n)²+(2/3)a²(-x²)^n
=(4/9)a^2x^(2n)+(2/3)a^2x^(2n)*(-1)^n
=(2/3+(-1)^n)*(2/3)a^2x^(2n)
(3m²n)*(三分之二m²n²)-(-10m)*m³n³
=(3m²n)*((2/3)*m²n²)-(-10m)*m³n³
=2*m^4*n^3+10*m^4*n^3
=12*m^4*n^3
好好学习~~
4x³y³(